Question

A gas has a volume of 25 L at a temperature of 100 K and a pressure of 1atm. if the temperature is increased to 300 K and the pressure increased to 6atm, what is the final volume gas?

Answer 1

In this question, since we are dealing with all 3 characteristics given to gases, we can use the Combined gas Law, which will show the relationship among all 3, temperature, volume and pressure, the formula for this law is:

P1V1/T1 = P2V2/T2

We have:

P1 = 1 atm

V1 = 25 L

T1 = 100 K

P2 = 6 atm

V2 = ?

T2 = 300 K

Now we add these values into the formula:

1 * 25/100 = 6 * V2/300

0.25 = 6V2/300

75 = 6V2

V2 = 12.5 Liters is the new volume