Notice how the left hand side has a common factor of 9xa on both terms.
Then, you can factorise a 9ax outside.
Now, in order to keep the equality the same, we need to divide the first term by 9ax. 45x³a/9ax can be rewritten as 9ax(5x²).
Let's do the same with the second term.
27xa²/9ax = 9ax(3a)
So, we have 9ax(5x²) + 9ax(3a) = 9ax(5x² + 3a)
So, our answer would be 5x² + 3a