Question

The answer tk this problem. There is more than one answer I think

Answer 1

Given:

`\angle A=40^0,\angle B=70^0`

Therefore,

`\begin{gathered} \angle C=180^0-(40^0+70^0)=70^0\text{ (The sum of the internal angles of the triangle is 180 degr}ees) \\ \therefore\angle C=70^0 \end{gathered}`

Then

Hence, the correct options are Option 2, 3, and 4.