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Find the coordinates of the vertex for the parabola -x^2-4+7
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Find the coordinates of the vertex for the parabola -x^2-4+7

User AllenSanborn
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1 Answer

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-X²-4+7
=-X²+3
a=-1 b=0
X=-b/2a
X=0
If X=0, Y=3
So the Vertex is (0, 3).
That's your answer.
User Debajit Mukhopadhyay
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