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Give the equation of the circle that is tangent to the y-axis and Center is (-3,2).

User Nezroy
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so... check the picture below

notice, the circle is tangent to the y-axis, namely, bordering it
so. surely you can see what the radius of it is

thus
\bf \qquad \qquad \textit{equation of a circle} \\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center\ ({{ h}},{{ k}})\qquad radius={{ r}}

use the provide h,k and get use the radius for "r"
Give the equation of the circle that is tangent to the y-axis and Center is (-3,2).-example-1
User Leem
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The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. If a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point. hope this helps

- Ava<3
User Yifat
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