Question

PLEASE HELP ME
In the following reaction, what element is made?

Answer 1

organic compounds is ur awnser

Answer 2

Answer:
`^(244)_(97)\textrm {Bk}`

Step-by-step explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is:

`^(241)_(95)\textrm{Am}+^(4)_(2)\textrm{He}\rightarrow ^(A)_(Z)\textrm {}+^(1)_(0)n`

To calculate A:

Total mass on reactant side = total mass on product side

`241+4=A+1`

`A=244`

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

95 + 2 = Z + 0

Z = 97

Thus the element will be berkelium with atomic number of 97 and element will be represented as
`^(244)_(97)\textrm {Bk}`