Question

Find the area of parallelogram ABCD given m2A=300 and the following measur 300 AX= 3 ft.; AB= 4V5 ft. A=

Answer 1

ABCD area =

AB = 4√2

AX= 3 ft = Height

then Area is

AREA= AB• AD • Sin 30°

THEN ANSWER IS

AREA= 4√2• 3 = 12√2 ft2

. = 17 square foots