Question

A local hamburger shop sold a combined total of 600 hamburgers and cheeseburgers on Thursday. There were 50 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Thursday?

Answer 1

let t = the total number of hamburgers and cheeseburgers, c = the total number of cheeseburgers, and h = the total number of hamburgers.

t = c + h where t = 600
c = h + 50

Use substitution to solve for h:

600=(h+50)+h
600= 2h+50
600-50=2h
550=2h
550/2=2h/2
h=275

therefore, 275 hamburgers were sold on thursday.