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3 votes
Which polynomial is factored completely?

A. g^5 -g

B. 4g^3+18g^2+20g

C. 24g^2-6g^4

D. 2g^2+5g+4

2 Answers

3 votes
Polynomial
D
all terms are different


User Spatialist
by
7.1k points
6 votes

Answer:

Option D. is the correct option.

Explanation:

We will factorize each polynomial given in the question.

A.
g^(5)-g=g(g^(4)-1)=g(g^(2)-1)(g^(2)+1)=g(g-1)(g+1)(g^(2)+1)

B.
4g^(3)+18g^(2)+20g=2g(2g^(2)+9g+10)=2g(2g^(2)+5g+4g+10)


=2g[g(2g+5)+2(2g+5)]=2g(2g+5)(g+2)

C.
24g^(2)-6g^(4)=6g^(2)(4-g^(2))=6g^(2)(2-g)(2+g)

D.
2g^(2)+5g+4 is factored completely.

Therefore answer is option D.

User Edwinc
by
7.3k points