Answer:
![0.05\ \text{kJ/kg}](https://img.qammunity.org/2022/formulas/physics/college/zw0t6rxs83697pgxshqglonyvr6bi4x8vw.png)
![3141.6\ \text{kW}](https://img.qammunity.org/2022/formulas/physics/college/1cpaopmvk0d5z9gq247qq8mo469obahoiy.png)
Step-by-step explanation:
v = Velocity of wind = 10 m/s
A = Swept area of blade =
![(\pi)/(4)d^2](https://img.qammunity.org/2022/formulas/physics/college/9fzwwbisp7nfpzn6wufg5e93fhekhbf2g2.png)
d = Diameter of turbine = 80 m
= Density of air =
![1.25\ \text{kg/m}^3](https://img.qammunity.org/2022/formulas/physics/college/i5fnf3rvs62jngnj9zq3wrv4xm23muhiof.png)
Wind energy per unit mass of air is given by
![E=(v^2)/(2)\\\Rightarrow E=(10^2)/(2)\\\Rightarrow E=50\ \text{J/kg}](https://img.qammunity.org/2022/formulas/physics/college/o9pydrg1a3fffegmi2kvbdikwednsje63p.png)
The mechanical energy of air per unit mass is
![0.05\ \text{kJ/kg}](https://img.qammunity.org/2022/formulas/physics/college/zw0t6rxs83697pgxshqglonyvr6bi4x8vw.png)
Power is given by
![P=\rho AvE\\\Rightarrow P=1.25* (\pi)/(4)* 80^2* 10* 50\\\Rightarrow P=3141592.65=3141.6\ \text{kW}](https://img.qammunity.org/2022/formulas/physics/college/22xyqz2b4ynd3uss8fvx2ygsmg40v5mmos.png)
The power generation potential of the wind turbine is
.