Question

Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumference by eye B: Measure the diameter with a ruler, then compute the circumference C: Measure the circumference with ruler and string D: Measure the circumference by rolling the ball along a ruler

Answer 1

Following are the solution to the given equation:

Explanation:

Please find the complete question in the attachment file.

In point a:

`\to \mu=(\sum xi)/(n)`

`=22.8`

`\to \sigma=\sqrt{(\sum (xi-\mu)^2)/(n-1)}`

`=\sqrt{(119.18)/(16-1)}\\\\ =\sqrt{(119.18)/(15)}\\\\ = √(7.94533333)\\\\=2.8187`

In point b:

`\to \mu=(\sum xi)/(n)`

`=20.6875`

`\to \sigma=\sqrt{(\sum (xi-\mu)^2)/(n-1)}`

`=\sqrt{(26.3375)/(16-1)}\\\\=\sqrt{(26.3375)/(15)}\\\\ =√(1.75583333)\\\\ =1.3251`

In point c:

`\to \mu=(\sum xi)/(n)`

`=21`

`\to \sigma=\sqrt{(\sum (xi-\mu)^2)/(n-1)}`

`=\sqrt{(2.62)/(16-1)}\\\\ =\sqrt{(2.62)/(15)} \\\\= √(0.174666667)\\\\=0.4179`

In point d:

`\to \mu=(\sum xi)/(n)`

`=20.8375`

`\to \sigma=\sqrt{(\sum (xi-\mu)^2)/(n-1)}`

`=\sqrt{(8.2975)/(16-1)}\\\\ =\sqrt{(8.2975)/(15)} \\\\ =√(0.553166667) \\\\ =0.7438`