Question

When a drag strip vehicle reaches a velocity of 60 m/s, it begins a negative acceleration by releasing a drag chute and applying its brakes. While reducing its velocity back to zero, its acceleration along a straight line path is a constant -7.5 m/s2 . What displacement does it undergo during this deceleration period

Answer 1

240 meters

Step-by-step explanation:

The distance traveled by the vehicle can be calculated using the following equation:

`v_(f)^(2) = v_(0)^(2) + 2ax` (1)

Where:

x: is the displacement

`v_(f)`: is the final speed = 0 (reduces its velocity back to zero)

`v_(0)`: is the initial speed = 60 m/s

a: is the acceleration = -7.5 m/s²

By solving equation (1) for x we have:

`x = (v_(f)^(2) - v_(0)^(2))/(2a) = (0 - (60 m/s)^(2))/(2*(-7.5 m/s^(2))) = 240 m`

Therefore, the vehicle undergoes 240 meters of displacement during the deceleration period.

I hope it helps you!