Register

Find the definite integral of 2^(lnx) from 0 to 1.

Find the definite integral of 2^(lnx) from 0 to 1.
130k views
4 votes
Find the definite integral of
2^(lnx) from 0 to 1.

User Aqib Javed
by
8.7k points

1 Answer

7 votes
Let y =
2^(lnx)
lnx = log₂y
lnx =
(lny)/(ln2)
lnx·ln2 = lny

y =
e^(lnxln2)
y =
x^(ln2)

∴ the integral of x^(㏑2) is
(x^(ln2+1))/(ln2 + 1)
So, with the bounds, it becomes:


(1)/(ln2 + 1)
User Amarnasan
by
7.9k points
← Prev Question Next Question →

Related questions

User Cheniel
asked Nov 17, 2020 48.0k views
Finding an Indefinite Integral dx/x(lnx^2)^3
Cheniel asked Nov 17, 2020
by Cheniel
8.0k points
1 answer
3 votes
48.0k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!