Question

Not a timed or graded assignment. In a rush so quick answer = amazing review :)

Answer 1

Answer: The percent yield of the process is 88.8% and the best option to answer the question is the third one (letter C)

Step-by-step explanation:

The question requires us to determine the percent yield of a reaction, given the experimental (or actual) yield - 10.3g of Ca(OH)2 - and the theoretical yield - 11.6g of Ca(OH)2.

We can calculate the percent yield from the actual and theoretical yield values using the following equation:

`\%\text{ }yield=\frac{actual\text{ yield}}{theoretical\text{ yield}}*100\%`

(note that both actual and theoretical yield must be in the same units of mass, in this case, the values are both in grams)

Applying the values provided by the question to the equation, we'll have:

`\%\text{ yield =}(10.3g)/(11.6g)*100\%=88.8\%`

Therefore, the percent yield of the process is 88.8% and the best option to answer the question is the third one (letter C).