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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts/million (ppm). A researcher believes that the current ozone level is not at a normal level. The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7. Assume the population is normally distributed. A level of significance of 0.02 will be used. Find the value of the test statistic. Round your answer to three decimal places.

User Aychedee
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1 Answer

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Answer:

The value of the test statistic is
t = 2.1

Explanation:

Our test statistic is:


t = (X - \mu)/((\sigma)/(√(n)))

In which X is the sample mean,
\mu is the expected value,
\sigma is the standard deviation and n is the size of the sample.

The level of ozone normally found is 7.5 parts/million (ppm).

This means that
\mu = 7.5

The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.

This means that
X = 7.8, \sigma = 0.7, n = 24

Test Statistic:


t = (X - \mu)/((\sigma)/(√(n)))


t = (7.8 - 7.5)/((0.7)/(√(24)))


t = 2.1

The value of the test statistic is
t = 2.1

User Zappa
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