Question

Find the distance d. Round your answer to the nearest tenth.Ty7654321123456789

Answer 1

SOLUTION AND EXPLANATION

The distance between two-point A and B is given as

`|AB|=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}`

From the diagram in the question the two-point given are

`\begin{gathered} A(1,3)\text{ } \\ B(6,6)^{} \end{gathered}`

Where

`x_1=1,x_2=6,y_1=3,y_2=6`

Substitute the parameters into the formula above

`\begin{gathered} |AB|=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ |AB|=\sqrt[]{(6-3)^2+(6-1)^2} \\ |AB|=\sqrt[]{3^2+5^2} \\ |AB|=\sqrt[]{9+25} \\ |AB|=\sqrt[]{34} \end{gathered}`

Hence, the distance between the two points is

`|AB|=5.8\text{units}`

Therefore the distance between the two-point is 5.8unit to the nearest tenth

The Third option is correct