31,020 views
16 votes
16 votes
what is the equation of the line of parallel to y=-3x+12, passing through (4,2), written in point-slope form and standard form?point-slope Form:y- = (x- )standard form: x+y=

User Tadas Davidsonas
by
2.8k points

1 Answer

17 votes
17 votes

Two lines are parallel if they have the same slope. The slope of y = -3x + 12 is -3.

The slope-intercept form is:

y = mx + b

where m is the slope and b is the y-intercept

Replacing with m = -3, and point (4, 2) into the equation, we get:

2 = -3(4) + b

2 = -12 + b

2 + 12 = b

14 = b

Then, the equation is:

y = -3x + 14

The standard form is:

Ax + By + = C

where A is a positive integer, and B and C are integers.

Reordering the previous equation:

3x + y = 14

User ComponentSpace
by
2.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.