Question

6x + 3y = 9
2x + 3y = 1
Solve the system of equations.

Answer 1

6x + 3y = 9
2x + 3y = 1

Subtract the equations from each other.

4x = 8

Divide both sides by 4.

x = 2

Plug in (2) for x in the first equation.

6x + 3y = 9

6(2) + 3y = 9

12 + 3y = 9

Subtract 12 from both sides.

3y = (9-12)

3y = -3

Divide both sides by 3.

y = -1

(2, -1)

~Hope I helped!~

Answer 2

Solution 1: 6(x) + 3(y) = 9
Solution 2: 2(x) + 3(y) = 1
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Your graphic organizer↓
3(y) + 6(x) = 9
3(y) + 2(y)= 1
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For the y-intercept; solution 2 ↓
"2" becomes a negative
3(y) which is equal to -2(x) + 1
Take off the "3" then this becomes y =
`(-2(x))/(3)` +
`(1)/(3)`
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Moving on to the x-intercept ; the first solution
6(x) + 3
`( (-2(x))/(3) ) + (1)/(9)` = 9
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We can simplify to find the x-intercept
4(x) = 8
the x-intercept is 2
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Lastly, we are looking for the y-intercept

`(-2(x) )/(3) + (1)/(3) = ?`

`-(2)/(3) (2) + (1)/(3) = -1`

So, the y-intercept is: -1
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Answer↓

`\left \{ {{x=2} \atop {y=-1}} \right.`

x-intercept: 2

y-intercept: -1