Question

How many moles of glucose (C6H12O6) are in 4.0 liters of a 4.5 M C6H12O6 solution?

Answer 1

Answer: 18 moles

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

`Molarity=(n)/(V_s)`

where,

n= moles of solute = ?

`V_s` = volume of solution in L = 4.0 L

Putting in the given values:

`4.5M=(n)/(4L)`

`n=18moles`

Thus 18 moles of glucose are present in 4.0 L of 4.5 M glucose solution.

Answer 2

molarity is the ratio of the moles of the solute over the volume of the solution in liters. In this case, we are given with 4.5 M or 4.5 mol/L which when multiplied by 4 liters of solution, the moles of glucose contained in the solution is equal to 18.0 moles of glucose.