Question

How many grams of oxalic acid dihydrate H2C2O4 ·2H2O, a diprotic acid, are needed to react with 20.00 mL of 0.4500 M NaOH?

Answer 1

With the given components above, the chemical reaction required to solve the problem is H2C2O4*2H2O + 2 NaOH = 4 H2O + Na2C2O4 where 1 mole of diprotic acid needs 2 moles of NaOH to complete the reaction.In this case, given 0.4500 M NaoH and 0.02 L of it, the moles diprotic acid needed is 0.0045 moles. This is equivalent to 0.351 grams.

Answer 2

`0.567gC_2H_2O_4.2H_2O`

Step-by-step explanation:

Hello,

The carried out chemical reaction is:

`HOOCCOOH+2NaOH-->NaOOCCOONa+2H_2O`

As long as the concentration of sodium hydroxide allows us to determine the reacting moles, we perform it as follows:

`n_(NaOH)=0.4500(molNaOH)/(L)*0.02000L=0.009000molNaOH`

Now, we can apply, the mole-mass relationship based on the chemical reaction:

`m_(C_2H_2O_4.2H_2O)=0.009000molNaOH*(1molC_2H_2O_4)/(2molNaOH)*(1molC_2H_2O_4.2H_2O)/(1molC_2H_2O_4) *(126g1molC_2H_2O_4.2H_2O)/(1gC_2H_2O_4.2H_2O)\\m_(C_2H_2O_4.2H_2O)=0.567gC_2H_2O_4.2H_2O`

Best regards.