Question

Factor.

100x^2 − 20xy + y^2

Answer 1

100x²− 20xy + y²=

(10x-y) (10x-y) or (10x-y)²

Answer 2

the factor of
`100x^2-20xy+y^2` are,
`10x-y` and
`10x-y`

Explanation:

Using the identity rule:

`(a-b)^2 = a^2-2ab+b^2`

Factor the given equation:

`100x^2-20xy+y^2`

We can write this as:

`10^2x^2-20xy+y^2`

Use:
`(ab)^2 = a^2 \cdot b^2`

⇒
`(10x)^2-2(10x)y+y^2`

Apply the identity rule:

`(10x-y)^2`

Therefore, the factor of
`100x^2-20xy+y^2` are,
`10x-y` and
`10x-y`