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Donnie is solving the equation 2x^2=27+3x with the quadratic formula. What values should he use for a , b , and c? A. a=2 b=27 c=3 B. a=2 b=-27 c=-3 C. a=2 b=3 c=27 D. a=2 b=-3 c=-27

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Answer:

The value of a,b and c is:


a=2,\ b=-3\ \text{and}\ c=-27

Explanation:

We know that any quadratic equation is given by the form:


ax^2+bx+c=0

and the formula which gives the solution of the equation is given by:


x=(-b\pm √(b^2-4ac))/(2a)

Here we have the equation as:


2x^2=27+3x

which is also given by:


2x^2-(27+3x)=0\\\\i.e.\\\\2x^2-27-3x\\\\2x^2-3x-27=0

i.e. on comparing with the general quadratic formula we have:


a=2,\ b=-3\ and\ c=-27

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