Question

Please help!!! Will mark!!

Find the zeros of the function f(x) = x^2 + 5x + 6.

A)y = 6 because the graph crosses the y-axis at 6.
B)y = -0.25 because that is the minimum value of the graph.
C)x = 2 and x= 3 because the graph crosses the x-axis at 2 and 3.
D)x = -3 and x = -2 because the graph crosses the x-axis at -3 and -

Answer 1

x^2+5x+6=0

x^2+2x+3x+6=0

x(x+2)+3(x+2)=0

(x+3)(x+2)=0

So the roots, zeros, or points where the graph touch the x-axis are when x=-2 and -3.