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For questions 1 and 2, use integer values of from –3 to 3 to graph the equation.

1) y = –2x2 + 3

User Kahlua
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1) y=-2x²+3 Therefore making a parabola
x -3 -2 -1 0 1 2 3
y -15 -5 1 3 1 5 15

2)y=1/3|x|-2
x -3 -2 -1 0 1 2 3
y -1 -1.3 -1.6 -2 -1.6 -1.3 -1
User Lulchenko Aleksey
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