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Does the sequence a1=1, a(n+1) = (an -1)/(an+1) converge?

1 Answer

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As defined, the sequence is not convergent.


\begin{case}a_1=1\\a_(n+1)=(a_n-1)/(a_n+1)&\text{for }n\ge2\end{cases}

\implies a_2=(1-1)/(1+1)=0

\implies a_3=(0-1)/(0+1)=-1

\implies a_4=(-1-1)/(-1+1)=-\frac20

but the last term is undefined.
User Rudydydy
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