Question

Solve the system below

y=x^2-2x-6
y=4x+10

A. (-2,2)
B. (8,42)
C. (-2,2),(8,42)
D. No real solution

Solve the system below  
y=x^2 -4
y= -4

A. (0,-4)
B. (-4,0)
C. (0,-4),(-4,0)
D. No real solution

Answer 1

For the system y=x^2-2x-6 & y=4x+10 the answer is A. (-2,2)
y=-2^2-2(-2)-6
y=4+4-6
y=8-6
y=2
y=4x+10
y=4 (-2)+10
y=-8+10
y=2




For the system y=x^2-4 & y=-4 the answer is
A.(0,-4)
y=0^2-4
y=-&
For the system