Question

N= 3, p=0.8, X= 2 Can someone help me

Answer 1

Answer = 0.384

Step-by-step explanation

This is a binomial distribution problem.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 3

x = Number of successes required = 2

p = probability of success = 0.8

q = probability of failure = 1 - p = 1 - 0.8 = 0.2

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

P(X = 2) = ³C₂ 0.8² 0.2³⁻²

P(X = 2) = 3 (0.64) (0.2) = 0.384

Hope this Helps!!!