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A hot air balloon climbs, at a 30 degree angle to the ground, to a height of 800 feet. To the nearest tenth of a foot, what ground distance has the balloon traveled to reach 800 feet?

User Quppa
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Final answer:

Using trigonometry, specifically the cosine of a 30-degree angle, the ground distance traveled by a hot air balloon climbing to a height of 800 feet is calculated to be approximately 923.5 feet.

Step-by-step explanation:

The student's question relates to trigonometry, a branch of mathematics that deals with the relationships between the sides and angles of triangles. Given that a hot air balloon climbs at a 30-degree angle to reach a height of 800 feet, we can find the ground distance traveled using the cosine function of that angle, as we are dealing with the adjacent side in a right-angled triangle.

To find the ground distance (d) we use the formula:

d = height / cos(angle)

Plugging in the values we get:

d = 800 ft / cos(30 degrees)

Using a calculator:

d ≈ 800 ft / 0.866

d ≈ 923.5 ft

User Vonette
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it would be 300 feet of 3 dergree
User Lowerkey
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