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If 12^x2+^5x-4=12^2x+6, what could be the value of x?

2 Answers

4 votes
Since the both have the same base 12 you can write like thus
X^2+5x-4=2x+6
X^2+5x-4-2x-6=0
X^2+3x-10=0
(X-2)(X+5)
X-2=0. X+5=0
X=2. And X=-5
User Xmindz
by
7.1k points
1 vote

Answer:


x=-5, x=2

Explanation:

we have


12^{(x^(2)+5x-4)}=12^((2x+6))

Since the both have the same base
12


{(x^(2)+5x-4)}={(2x+6)}


x^(2)+5x-4-2x-6=0


x^(2)+3x-10=0

Using a graphing tool ------> resolve the quadratic equation

see the attached figure

The solutions are


x=-5, x=2

If 12^x2+^5x-4=12^2x+6, what could be the value of x?-example-1
User Evan Siroky
by
6.9k points