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What is the probability of drawing a diamond from a standard deck of cards on a second draw, given that a diamond was drawn on the first draw and not replaced?

User Mkersten
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2 Answers

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There are 52 cards in a deck of cards there 13th of each kind

So it's 13/52. X 12/52
User Neil Barnwell
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Answer:

The probability is 0.058.

Explanation:

Given : A standard deck of cards and a diamond was drawn on the first draw and not replaced.

To find : The probability of drawing a diamond from a standard deck of cards on a second draw, given that a diamond was drawn on the first draw and not replaced?

Solution :


\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

In a standard deck of 52 cards,

13 diamonds , 13 club , 13 hearts , 13 spade

On a first drawn,

Favorable outcome (diamond was drawn) = 13

Total number of outcome = 52

Probability of first drawn is


\text{Probability}=(13)/(52)

On a second drawn given that first drawn is not replaced,

Favorable outcome (diamond was drawn) = 12

Total number of outcome = 51

Probability of second drawn is


\text{Probability}=(12)/(51)

Now, The probability of drawing a cards with the given situation is


\text{Probability}=(13)/(52)*(12)/(51)


\text{Probability}=(156)/(2652)


\text{Probability}=0.058

Therefore, The probability is 0.058.

User Joshaven Potter
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