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The sum of two numbers is forty. The difference between twice the smaller and forty-two is negative fourteen. Find both numbers

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X is the smaller number
X+y=40
2x-42=-14

Solve for x
2x= -14+42
2x= 28
Divide both sides by 2
X= 14
2x-42=-14

14+y=40
Subtract 14
Y= 26
User James Mitchell
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