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If x equals negative 2 and y equals the square root of 12, then begin expression . . . 2 times the quantity . . . 3 times x raised to the third power, plus 2 times y raised to the second power . . . end expression . . . equals

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I don't understand your question, expressions do not end with equal signs. Or are you just asking how to write the expression?

2*((3*x)^3)+2(y^2) then simply replace the x with "-2" and y with "sqrt(12)"
2*(-2)^3+2(12)
-16+24
8
User Nafees Anwar
by
8.0k points
3 votes

Answer:

The value of given expression at x = -2 and y =
√(12) is 0

Explanation:Given expression : 2 times the quantity 3 times x raised to the third power, plus 2 times y raised to the second power .

WE have to evaluate the value of given expression at x equals negative 2 and y equals the square root of 12 that at x = -2 and y =
√(12)

Given expression can be represented mathematically as,


2(3x^3+2y^2)

First we simplify the given expression,


\Rightarrow 2(3x^3+2y^2)

Put x = -2 and y =
√(12) , we get


\Rightarrow 2(3(-2)^3+2(√(12))^2)

On simplifying, we get,


\Rightarrow 2(3(-8)+2(12)


\Rightarrow 2(-24+24)


\Rightarrow 2(0)


\Rightarrow 0

Thus, the value of given expression at x = -2 and y =
√(12) is 0

User MurgleDreeBrah
by
8.3k points

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