Answer:
A. The function f(x) has the higher initial amount of bacteria.
B. The function g(x) has the higher amount of bacteria after two days.
Explanation:
The given function is

The graph of g(x) passing through the points (0,1000) and (1,3000). So the initial value is 1000 and the growth factor is 3.
The function g(x) is

Part A:
Substitute x=0, to find the initial blue of the functions.


Since 2000>1000, therefore the function f(x) has the higher initial amount of bacteria.
Part B:
Substitute x=2, to find the amount of bacteria after two days.


Since 8000<9000, therefore the function g(x) has the higher amount of bacteria after two days.