Question

What volume of H2O(g) is produced when 8.90 mol of C2H4(g) reacts at STP?

Answer 1

This question uses Ideal Gas Law, whose equation is as follows:

PV = nRT

P = pressure = 1 atm
V = volume = unknown
n = moles = 8.90 mol
R = gas constant = 0.082
T = temperature = 273. K

Since we are solving for Volume, you can rearrange the formula to get V alone:


`V= (nRT)/(P)`

Plug in the given values and solve:


`V= ((8.90mol)(0.082)(273. K))/(1 atm)`

V = 199.2354 L

Round to the necessary significant digits