Question

Air pressure decreases exponentially with increases in elevation. The air pressure, y, (in atm units) at a given elevation, x, (in meters) can bemodeled using equation y = e where k is the decay constant.At an elevation of 5486 m where the air pressure is 0.5 atm, what is the value of k?O A k=In( 5486)0.5B. k =In(0.5)548654860.5D. k = - In ( 3956

Answer 1

Take natural log on both side of the equation to simplify it,

`\begin{gathered} \ln y=\ln (e^(-kx)) \\ \ln y=(-kx)\ln e \\ \ln y=-kx \\ k=(-\ln y)/(x) \end{gathered}`

S