Question

What must the charge (sign and magnitude) of a particle of mass 1.40 gg be for it to remain stationary when placed in a downward-directed electric field of magnitude 640 N/CN/C

Answer 1

the charge of the particle is -2.144 x 10⁻⁵ C.

Step-by-step explanation:

The force acting on the particle is calculated as;

F = EQ = mg

`Q = (mg)/(E)`

where;

Q is magnitude of the charge of the particle

`Q = ((1.4* 10^(-3))(9.8))/(640) \\\\Q = 2.144 \ * \ 10^(-5) \ C`

since the magnetic field is acting downward, the force must be acting upward in opposite direction.

Thus, the charge of the particle will be -2.144 x 10⁻⁵ C.