Question

What is the voltage of a battery that powers a light with .43 a and has a resistance of 3.5 ohms?

Answer 1

V = IR

V = 0.43*3.5= 1.505

Answer 2

The voltage of the battery is
`1.505V`

Step-by-step explanation:

To answer this question we are going to use the Ohm Law.

Ohm Law is a law that states that the voltage across a resistor is directly proportional to the current flowing through the resistance multiply by the value of the resistance.

Mathematically, we can write :

`V=I.R` (I)

Where V is the voltage

Where I is the current

And where R is the resistance

The unit of voltage is V which is volt

The unit of current is ''a'' which is ampere

And the unit of resistance is ohm

If we replace all the data in equation (I) :

`V=I.R`

`V=(0.43a).(3.5ohm)=1.505V`

The voltage of the battery is
`1.505V`