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Two point charges, A and B, are separated by a distance of 19.0 cm . The magnitude of the charge on A is twice that of the charge on B. If each charge exerts a force of magnitude 45.0 N on the other, find
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Oct 3, 2022
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Two point charges, A and B, are separated by a distance of 19.0 cm . The magnitude of the charge on A is twice that of the charge on B. If each charge exerts a force of magnitude 45.0 N on the other, find the magnitudes of the charges.
Physics
college
Thanasis Petsas
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Answer:
QA = 19μC
QB = 9.5 μC
Step-by-step explanation:
The force that each charge exerts on the other must obey Coulomb's Law, as follows:
We know that the value of the magnitude of FAB is 45.0 N, the distance between QA and QB is 0.19 m, and that QA = 2*QB.
Replacing in (1), we can solve for QB, as follows:
Since QA = 2*QB
⇒
QA = 2* 9.5μC = 19.0 μC
⇒ QB = 9.5μC
Angery
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Oct 8, 2022
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