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John rolls a six-sided number cube twice. What is the probability of getting an even number and then an odd number?

5/6
1/4
1/2
1/6

User BladeMight
by
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1 Answer

3 votes

Answer:

Option 2 -
\text{Probability}=(1)/(4)

Explanation:

Given : John rolls a six-sided number cube twice.

To find : What is the probability of getting an even number and then an odd number?

Solution :

When rolls a six-sided number cube twice

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now,


\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Favorable outcome of getting an even number and then an odd number:

(2,1) (2,3) (2,5) (4,1) (4,3) (4,5) (6,1) (6,3) (6,5)

So, Favorable outcome = 9

Total number of outcome = 36


\text{Probability}=(9)/(36)


\text{Probability}=(1)/(4)

Therefore, Option 2 is correct.

User Jmlsteele
by
7.8k points

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