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A ball is thrown from an initial height of 2 meters with an initial upward velocity of 20 m/s. The ball's height h (in meters) after t seconds is given by h=2+20t-5t^2. find all values of t for which the ball's height is 12 meters. Round your answers to the nearest tenth of a second.

User Bente
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1 Answer

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So 12 = 2 + 20t -5t^2

5t^2 -20t + 10=0

t^2 -4t + 2 = 0

Use quadratic formula to solve
User Gilletty
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