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he potential energy between two atoms in a particular molecule has the form U(s) = 2.6/x^8 - 4.3/x^4 where the units of x are length and the numbers 2.G and 4.3 have appropriate units so that U(x) has units of energy. What b the equilibrium separation of the atoms (that is the distance at which the force between the atoms is zero)?

User Nevster
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1 Answer

10 votes

Answer:

x = 1.04866

Step-by-step explanation:

Force can be defined from power energy by the expressions

F =
- ( dU)/( dx)

in this case we are the expression of the potential energy

U =
(2.6)/(x^(8) ) - (4.3)/( x^(4) )

let's find the derivative

dU / dx = 2.6 (
(-8)/(x^(9) )) - 4.3 (
(-4)/( x^(5) ))

dU / dx =
- (20.8)/( x^(9) ) + (17.2 )/( x^(5) )

we substitute

F = + \frac{20.8}{ x^{9} } - \frac{17.2 }{ x^{5} }

at the equilibrium point the force is zero, so


(20.8)/( x^(9) ) = (17.2)/( x^(5) )

20.8 / 17.2 = x⁴

x⁴ = 1.2093

x =
\sqrt[4]{ 1.2093}

x = 1.04866

User Lukk
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