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If a normal distribution has a mean of 62 and a standard deviation of 12 what is the z-score for a value of 80

a:1
b:1.5
c:2
d:0.5

2 Answers

5 votes

Answer:

Option B:→ 1.5

Explanation:

User Dnlbrky
by
8.6k points
4 votes

Answer with explanation:


\text{Mean}=\mu = 62\\\\ \text{standard deviation}=\sigma=12\\\\ \bar X=80\\\\Z_(score)=(\bar X -\mu)/(\sigma)\\\\Z_(score)=(80-62)/(12)\\\\Z_(score)=(18)/(12)\\\\Z_(score)=1.5

Option B:→ 1.5

User Fibnochi
by
8.0k points

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