Question

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

The 2010 world-record pumpkin weighs _____ kilograms more than an average-sized pumpkin?

Answer 1

1805kg more. 1000g=1kg so 5000g=5kg then 1810kg-5kg=1805kg

Answer 2

1,805 kilograms more.

Explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

First of all, we will convert 5,000 grams to kilograms by dividing 5,000 by 1000 as 1 kg equals 1000 grams.

`\text{5,000 grams}=(5,000)/(1,000)\text{ kg}`

`\text{5,000 grams}=5\text{ kg}`

Now, we will subtract 5 kg from 1810 kg.

`1,810\text{ grams}-5\text{ kg}=1,805\text{ kg}`

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.