Question

What is the area of the sector of the circle below, if the radius is16 m. and the central angle < AOB measures 62°. (round answer to the nearest tenth)

Answer 1

To determine the area of the shaded sector, we use the formula below.

`A=(\theta)/(360\degree)(\pi r^2)`

Based on the question, the given information are:

• radius = 16 meters

,

• central angle = 62°

,

• pi value = 3.14159

Let's plug the given information into the formula above.

`A=(62)/(360)(3.14159)(16m)^2`

Then, solve.

`A=0.17222(3.14159)(256m^2)`
`A=138.509\approx138.5m^2`

Therefore, the area of the shaded sector is approximately 138.5m². (Option C)