Question

What mass of silver nitrate, AgNO3, is required to prepare 800. g of 3.50% solution of AgNo3

Answer 1

3.5 % of 800 g = 28 grams of AgNO3

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Answer 2

28 g of AgNo3

Step-by-step explanation:

800 g of 3.5% solution of AgNo3 is to be prepared.

3.5% AgNo3 solution contains 3.5g of AgNo3 in 100 g of solution.

If 3.5 g AgNo3 is present in 100 g of solution, then how many g is needed to make 800 g of solution?

3.5 g AgNo3..........................100 g solution

X g AgNo3.......................... 800 g solution

X g AgNo3 = 3.5 x 800/100

= 28 g

Hence, 28 g of AgNo3 will be required to prepare 800 g of 3.5% solution of AgNo3.