Question

PLEASE HELP!!

A line passes through(3,-2) and (6,2)
Write the equation for the line in point-slope form and rewrite the equation in slope-intercept form
A.y-3=4/3(x+2);-4x+3y=17
B.y+2=4/3(x+3);4x+3y=-18
C.y+2=4/3(x-3);-4x+3y=-18
D.y-2=4/3(x-3);4x+3y=18

Answer 1

Hello:
let A(3,-2) and B (6,2)
The slope is : a = (YB -YA)/(XB -XA)
a = (2-(-2))/(6-3)
a =4/3
C) .y+2=4/3(x-3);-4x+3y=-18
because : A(3,-2) : -2+2=4/2(3-3) ...... 0=0
B (6,2) : 2+2 =4/3(6-3) .... 4 = 4