Answer:
Yes
Step-by-step explanation:
Given that :
CHAIN A:
Sample size n1 = 30
Sample standard deviation of waiting time s1 = 21.2
CHAIN B:
Sample size, n2 = 28
Sample standard deviation of waiting time s2 = 31.4
Null hypothesis H0: s1 = s2
Alternative hypothesis H1: s1 < s2
Test statistic ; Ftest : s1² / s2²
Ftest = 21.2^2 / 31.4^2
= 0.4558399
P value from F statistic : = 0.02 (using p value calculator)
Since the pval < 0.05
Then we reject the Null ; Chain A waiting time is more consistent