126,731 views
36 votes
36 votes
Write the equation of the function graphed below: x) =x√3x3– 4f(x) =x√3x3+ 4f(x) = 2x√3x3+ 4f(x) = 2x√3x3–4

Write the equation of the function graphed below: x) =x√3x3– 4f(x) =x√3x3+ 4f(x) = 2x-example-1
User JonWarnerNet
by
3.0k points

1 Answer

9 votes
9 votes

The graph is showing the behaviour of the function x^1/2, then, let's start with it:


f(x)=\sqrt[]{x}

Now, we try to reach the given graph by multiplying and adding numbers to f(x). Firstly, the graph is always negative, so we multiply f(x) by -1.


g(x)=-\sqrt[]{x}

Then, let's move the graph five units to the positive x position. To do so, we can add -5 to the x.


h(x)=-\sqrt[]{x-5}

Finally, we need to multiply the function so that the curve opens at the rate of the given graph.


m(x)=-2\cdot\sqrt[]{x-5}

As you can see, the graph is changing as we add or multiply by some factors. the red curve is pretty close to the given graph.

Write the equation of the function graphed below: x) =x√3x3– 4f(x) =x√3x3+ 4f(x) = 2x-example-1
User Mohammad Al Alwa
by
2.6k points