Question

a flat screen television has a length that is 1 more inch than its width the area of the television screen is 1500 in . to the nearest whole inch what are the dimensions of the television?

Answer 1

w+1=l
area=lw
area=(w+1)w
1500=w²+w
minus 1500 both sides
0=w²+w-1500
use quadratic formula
for
aw²+bw+c=0

`w= (-b+/- √(b^2-4ac) )/(2a)`


`w= (-(1)+/- √(1^2-4(1)(-1500)) )/(2(1))`

`w= (-1+/- √(1+6000) )/(2)`

`w= (-1+/- √(6001) )/(2)`
77.466121627457250675410729387462

`w= (-1+/- 77.466121627457250675410729387462)/(2)`
it can't be minus since measures cannot be negative

`w= (-1+ 77.466121627457250675410729387462)/(2)`

`w= (76.466121627457250675410729387462)/(2)`
w=38.233060813728625337705364693731
to nearest whole
w=38
l=38+1=39

the dimentions are 38 by 39 inches