In order to find how many milliliters of .100 M NaOH are required to neutralize the following solution 75.5mL of .215 M H2SO4, we will use the following formula :
M1*V1 = M2*V2
Where M1 =0.215
V1=75.5ml
M2 =0.100
V2 =?
∴ V2 = M1*V1/M2
= 0.215M* 75.5ml/0.100M
= 162.33 ml
• This means that ,162.33 milliliters, of 0.1M NaOH will be required,